Chemistry, 28.09.2019 05:30 traybrown0690
Part b - the effect of an electric field (voltage) on a negatively charged oil droplet in the millikan oil droplet experiment, the oil is sprayed from an atomizer into a chamber. the droplets are allowed to pass through the hole into the chamber so that their fall can be observed. the top and bottom of the chamber consist of electrically charged plates. the upper plate is positively charged, and the lower plate is negatively charged. x rays are introduced into the chamber so that when they strike the oil droplets, the droplets will acquire one or more negative charges. the electric field (voltage) is applied to the metal plates. watch the animation and identify the effects of an electric field on the motion of a negatively charged oil droplet. consider the gravitational force as fg and the electric force as fe. all the other forces acting on the oil droplet can be ignored as their effect on the motion of the oil droplet is negligible. check all that apply.
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Percent ionization for a weak acid (ha) is determined by the following formula: percent ionization=[ha] ionized[ha] initial×100%for strong acids, ionization is nearly complete (100%) at most concentrations. however, for weak acids, the percent ionization changes significantly with concentration. the more diluted the acid is, the greater percent ionization.a certain weak acid, ha, has a ka value of 9.4×10? 7.part acalculate the percent ionization of ha in a 0.10 m solution.part bcalculate the percent ionization of ha in a 0.010 m solution
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Part b - the effect of an electric field (voltage) on a negatively charged oil droplet in the millik...
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