Atypical person has an average heart rate of 75.0 beats/min. calculate the following a)how many beats does she have in 7.0 years? b) how many beats in 7.000 years? pay close attention to significant figures in this question.

a) Beats in 7.0 years =

b) Beats in 7.000 yrs=

Explanation:

Step 1

Calculation of no. of min. in 7 year

Days in a year = 365

Hrs in a day = 24

Min. in a 1 hr = 60

Min. in a day = 60 × 24

Min. in a year = 60 × 24 × 365

Min. in 7 years

               = 60 × 24 × 365 × 7

               = 3679200 min.

a) Beats in 7.0 years

Heart rate = 75.0 beats/min.

Beats in 7.0 yrs

             = 75.0 × 3679200

             = 275940000 beats

No. of significant figure = 2

Answer has to be reported in 2 significant digits.

Beats in 7.0 years =

a) Beats in 7.000 years

Beats in 7.000 yrs = 275940000 beats

No. of significant figure in 7.000 = 4

Answer has to be reported in 4 significant figures

So, no. of beats in 7.000 yrs=

wher is the rest of the question