How many grams of ethyl alcohol would be needed to produce 104.5 g of diethyl ether if the percent yield of reaction is 83.4 % ?

The reaction to convert ethyl alcohol to diethyl ether with the use of concentrated sulfuric acid as a catalyst at 140°C, and with excess ethanol. The reaction is written below:

2 CH₃CH₂OH  →  CH₃CH₂OCH₂CH₃  + H₂O

The molar mass of diethyl ether is 74 g/mol while that of ethanol is 46 g/mol. The solution is as follows:

(104.5 g diethyl ether)*(0.834)*(1 mol diethyl ether/74 g)(2 mol ethanol/1 mol diethyl ether)*(46 g ethanol/mol) = 108.35 g ethanol needed

All the elements are arranged by melting points on the periodic table. in row they go from metals to gasses. in the row from sodium to argon, sodium is more reactive than the one on its right, magnesium.