Consider the balanced chemical equation that follows. you are asked to determine how many moles of water you can produce from 4.0 mol of hydrogen and excess oxygen. (excess oxygen means that so much oxygen is available it will not run out.) which of the numbers that appear in the balanced chemical equation below are used to perform this calculation? 2h2(g)+o2(g)→2h2o(l)

4 moles of water are produced.

Number 2 is used to perform this calculation

Explanation:

The balanced chemical equation is:

As it is given, excess oxygen is present, oxygen acts as excess reagent and hydrogen acts as limiting reagent as it limits the formation of products

According to stoichiometry:

2 moles of hydrogen give = 2 moles of water

Thus 4 moles of hydrogen give = moles of water

4 moles of water are produced . Thus the coefficient 2 from hydrogen and coefficient 2 from water that appear in the balanced chemical equation is used.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

the answer would be b i believe