The reaction ch3-n ≡ c → ch3-c ≡ n is a first-order reaction. at 230.3°c, k = 6.29 ⋅ 10-4s-1. if [ch3 = n≡c] is 1.00 ⋅ 10-3 initially, [ch3 = n≡c] is after 1.000 ⋅ 103 s.

The answer is 5.33 x 10^-4

to find the answer follow these steps:

the reaction is first order reaction

here k = 6.29 x 10^-4 s^-1

initial concentration = 1.00 x 10^-3

After time t = 1.000 x 10^3 s concentration is = ?

So, - 6.29 x 10^-4 x 1.00 x 10^3 + ln (1.00 x 10^-3) = - 7.54 

C = e ^ - 7.54= 5.33 x 10^-4 M

odds are decent that your handwriting right now looks a little bit different than it did five years ago, and will look different again in five more. when i look back through my notebooks from middle school to now, i see a long, slow progression from meticulous and teeny letters to bigger, sloppier ones, plus a few side detours: sometime in high school, for example, i decided those loopy cursive lowercase f’s were just the coolest, adopting them as the lone rep for cursive in my otherwise all-print handwriting.

explanation: