Calculate the wavelength of the laser light for a) d = 1/500 mm and b) d = 1/1000 mm. use the modified “grating equation” given below: nλ = d (x/l) remember to keep all calculations in millimeters (mm) until the end and then convert your answer to nanometers (1 nm = 10‐6 mm). show all your work below:

The grating equation comes from the concept of diffraction grating where the light is split into slits or bands and diffracted intro several beams travelling in different directions. The equation given is

nλ = d (X/L)
where
n is the order of fringe
λ is the wavelength of light
d is the distance between the slits
x is the distance from the central fringe
L is the length of the screen with slits to the viewing screen

Now, if we're only given with d, we cannot solve the problem because we don't know the values for n, x, and L. So, let's just assume for sample purposes. As mentioned earlier, light is diffracted into bands. The middle band is called the central fringe where n=0. If the wavelength of the specific light having a certain band is located next to the central fringe, n=1. If it is located two places from the central fringe, n=2, and so on and so forth. Let's assume n=3. Next, let us also assume that the screen are place 13.7 m apart, so L=13.7 m. To complete the data, let's assume x=25 mm. Substituting the values:

a.) (3)λ = (1/500 mm) (25 mm/13,700 mm))
      λ = 1.217×10⁻⁶ mm or 1.217 nm

b.) (3)λ = (1/1000 mm) (25 mm/13,700 mm))
      λ = 6.083×10⁻⁶ mm or 6.083 nm

I’d have to say no because without oxygen in the water the fish would all be dead. so if you want to fish for dead fish, pick the ponds with the lowest oxygen concentrations.

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.