What volume of 0.0250 m calcium hydroxide is required to neutralize 33.50 ml of 0.0200 m nitric acid?

The chemical formula for calcium hydroxide is Ca(OH)₂ and that of nitric acid is HNO₃. By these chemical formula it can be deduced that the number of equivalents per mole of Ca(OH)₂ is 2 because of 2 OH⁻ and for HNO₃ is 1 because of H⁺.

For the neutralization reaction, the number of equivalents should be equal. 
             V₁n₁ = V₂n₂

Substituting the known values and with the incorporation of the concept above,
     (V₁)(0.0250 mol/L)(2 equivalents/mol) = (33.50 mL)(0.020 mol/L)(1 equivalent/mol)

         V₁ = 13.4 mL

Hence, the volume of calcium hydroxide needed is approximately equal to 13.4 mL. 

True, the standard unit for volume is liters which can be represented by either a lower case "l" or a capital "l"