How many liters of water must be added to 5.40 g of sodium nitrate to create a solution that has a concentration of 3.81 g/l?

Hey there !

Mass of solute = 5.40 g

Concentration = 3.81 g/L

Volume =  ?

therefore :

C = m / V

3.81 = 5.40 / V

V = 5.40 / 3.81

V = 1.417 L

True is ur answer : )

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