Find the no. of electron involved in the electro deposition of 63.5g of cu from a solution of cuso4

This is a redox reaction, meaning reduction-oxidation reaction. This represents the reaction in one side of the electrode in an electrolysis set-up. First, we find the oxidation number of Cu in CuSO4:

(ox. # of Cu)+ ox.# of S + 4(ox.# of oxygen) = 0
(ox. # of Cu) + (6) + 4(-2) = 0
ox. # of Cu = 2+

CuSO4 ---> Cu + SO42-
Cu2+ + SO42-  >  Cu + SO42-
Cu2+ > Cu + 2e-   (net ionic reaction)

The stoichiometric equation would be 2 electrons per mole Copper. Copper has a molar mass of 63.5 g/mol. Then, it would only need 2 electrons.

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