What would be the volume in liters of an ideal gas, if a 0.425 mole sample of the gas had a temperature of 900 degrees celsius at a pressure of 3.00 atmospheres? (the ideal gas constant is 0.0821 l•atm/mol•

The ideal gas law relates the pressure (P), volume (V), number of moles (n), and temperature (T) of a given ideal gas through the equation,

                                 PV = nRT 

If we are to determine the volume of the gas, we derive the equation such that it takes the form of,
                                 V = nRT/P

Substituting,
             V = (0.425 mol)(0.0821 L.atm/mol.K)(900 + 273 K) / 3 atm

                            V = 13.64 L

Thus, the volume of the ideal gas is approximately 13.64 L. 

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Answer : option a) 84explanation :

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.