Type in the correct values to correctly represent the valence electron configuration of oxygen: asb2pc
a =
b =
c =

The correct number of valance electrons in the electronic configuration of Oxygen is:

A=2, B=2, and C=4

Explanation:

The atomic number of oxygen is 8

The electronic configuration will be,

The electrons present in the outermost shell is called valence electrons.

Hence, in the second shell, the s-orbital contains 2 electrons and the p-orbital contains 4 electrons.

If all the electrons in the outermost shell are removed the first shell becomes a valance shell where 2 electrons are present in the s-orbital.

Therefore correct valence electron configuration is 2,2,4.

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A=2,  B=2 and  C=4

Explanation: Oxygen is the element with atomic number 8 and thus contains 8 electrons which are filled in order of increasing energy levels.

The valence electrons are electrons which are present in the valence shell i.e. the last shell. Thus the valence electrons of Oxygen are in shell 2 in which s orbital contains two electrons and the p orbital contains 4 electrons.

Thus A= 2, B=2 and C=4.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

c (diamond),

sio2 (quartz)