When the volume of a gas is changed from 3.6 l to 15.5 l, the temperature will change from oc to 87°c

The
When the volume of a gas is changed from 3.6 L to 15.5 L, the temperature will change from  ?? oC to 87°C

application of charles law

charle's law tells that 

T1/ V1 = T2 / V2, T must be in kelvin

it is given that  V1 = 3.6 L, V2 = 15.5 L, 
T2= 87°C= 360.15 K

so to find T1,  T1 =(T2 / V2) x V1

T1= (360.15 / 15.5) * 3.6= 83.64° K = - 190.15° C

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