How many grams of sodium sulfide can be produced when 45.3 g na react with 105 g s?

unbalanced equation: na + s → na2s

my
balance the equation: 2na + s --> na2s
using the given amount of the reactants in the reaction, calculate the amount of the product:
45.3g na x (1 mol/22.99 g)= 1.97 mol of na
105f s x (1 mol/ 32.06g) = 3.28 mol of s
the limiting reactant would be na:
1.97 mol na x (1 mol na2s/ 2 mol na) x (78.04g/mol) = 76.87g of na2s produced