The following equations are half reactions and reduction potentials. li+ (aq) + e- mc009-1.jpg li(s) has a reduction potential of –3.04 v f2(g) + 2e- mc009-2.jpg 2f-(aq) has a reduction potential of +2.87 v now consider lithium (li+) and fluoride (f2) as oxidizing agents. how do these compare as oxidizing agents? lithium is a stronger oxidizing agent than fluoride. fluoride is a stronger oxidizing agent than lithium. fluoride and lithium have the same oxidizing strength. reduction potential and oxidizing/reducing strength are unrelated.