What mass of li3po4 is needed to prepare 500 ml of a solution having a lithium ion concentration of 0.175 m?

Explanation:

The first step is to find the moles of  , using the equation:

Where,

Plug in the values into the equation:

Solving for mole:

Now, the have to write the chemical equation to find the molar ratio between and , so:

The molar ratio then is 1:3, using this molar ratio we can convert from moles of to moles of , so:

Finally, we have to conver from moles of to grams of   using the molar mass of (115.79 g/mol), so:

it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2