By examining electron domain geometry, one can determine that the ammonia molecule (nh3) has
(a)one sp2 orbital.
(b)two sp2 orbitals.
(c)three sp3 orbitals.
(d)four sp3 orbitals.

The correct answer is Option D.

Explanation:

Hybridization is calculated by using the formula:

where,

V = number of valence electrons present in central atom i.e. nitrogen = 5  

N = number of monovalent atoms bonded to central atom = 3

C = charge of cation = 0

A = charge of anion = 0

Putting values in above equation, we get:

The number of electron pairs comes out to be 4 which means that the hybridization of the given compound will be .

Hybridization is intermixing of orbitals of similar energy to form new hybrid orbitals. Thus, in , 1 s-orbital and 3 p-orbitals are combining to form 4 orbitals.

Hence, the correct answer is Option D.

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