What is the empirical formula of a compound that is 62.0% c, 10.4% h, and 27.5% o by mass?

The empirical formula for the given compound is

Explanation:

We are given:

Percentage of C = 62.0 %

Percentage of H = 10.4 %

Percentage of O = 27.5 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 62.0 g

Mass of H = 10.4 g

Mass of O = 27.5 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =

Moles of Hydrogen =

Moles of Oxygen =

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 1.72 moles.

For Carbon =

For Hydrogen  =

For Oxygen  =

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 6 : 1

Hence, the empirical formula for the given compound is

Mass is the amount of matter in an object.  weight is the measurement of the pull of gravity on an object.  say for example, you travel to the moon which has a different gravitational field compared to the gravitational field of earth. (gravitational fields: earth = 1, moon = 0.165)  now when you are on the moon, the pull of gravity on you is different than on the earth. and as weight is the measurement of the pull of gravity on an object, that means yes, your weight can and will change on the moon.  however, on the moon, on earth or even on jupiter, the amount of mass inside of you remains the same. meaning your physical mass remains constant.  in conclusion it is possible for your weight to change as your mass remains constant. 

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