How many grams of naoh are required to prepare 240 ml of a 3.50 m naoh solution?

Explanation:

We have to start with the molarity equation:

Where:

M= 0.35

L=0.24

(We have to remember that we need to convert the mL into L using the conversion ratio 1 L = 1000 mL). Then with these two values we can calculate the  moles of NaOH on this solution, so:

The next step is the conversion from mol to grams. To do this we have to calculate the molar mass of NaOH. So, we have to find the atomic mass of each atom in the compound, so:

Na => 23 g/mol

O => 16 g/mol

H => 1 g/mol

When we add all these values we will have a value of 40 g/mol for NaOH. Now, we can calculate the grams in the 0.084 mol of NaOH:

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.