Iron has a density of
7.86 g/c
m
3
(
1 c
m
3
=1 ml
). calculate the volume (in
dl
) of a piece of iron having a mass of 4.58
kg
. note that the density is provided in different units of volume and mass than the desired units of volume (
dl
) and the given units of mass (
kg
). you will need to express the density in
kg/dl
(
1 c
m
3
= 1 ml
) before calculating the volume for the piece of iron.

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

This is a solution, hope i could