If you start witg 14.8g of c3h8 and 3.44g of o2, determine the limiting reagent

Firstly write down the equation:

C3H8 + 5O2 = 3CO2 + 4H20

THEN Calculate the number of mole of each of them
ME OF C3H8 =44
n(C3H8) = (14.8) / 44 =0.336
n(O2) =x (calculate it )

do the same for oxygen then
followed by that

use mole ratio 1 mole of C3H8 react with 5 mole of O2,

BUT  YOU USE ONLY x MOLE OF O2\

if u still have any problem please feel free...