If 27.3 ml of 0.293 m hbr solution completely neutralizes 42.6 ml of nh3, what is the concentration of the nh3 solution? nh3 + hbr yields nh4br 0.188 m 0.387 m 0.586 m 2.18 m

According to reaction equation: NH3+HBr=NH4Br, 1 mole of NH3 is required to react with 1 mole of HBr.  HBr solution contains 0.0273L * 0.293M = 0.008 moles of HBr.  Therefore 0.008 mole of NH3 is reacted. So the concentration of NH3 is 0.008 mole/0.0426 L = 0.188M.  The answer is 0.188M.

Abbreviated as mg-25.