Pcl5 => pcl3+cl2
the no of moles of cl2 produced will be if one mole of pcl5 is heated 250c in vessel having a capacity of 10dm^3. at 250°c kc= 0.041

0.47 moles

Explanation:

Initial moles of   = 1 mole

Volume of container =

Initial concentration of  

The given balanced equilibrium reaction is,

Initial conc.         0.1 M             0    0

At eqm. conc.    (0.1-x) M   (x) M   (x) M

The expression for equilibrium constant for this reaction will be,

Solving for x:

Thus concentration of produced is 0.047 M

where,

n= moles of solute  

= volume of solution in L

Thus moles of produced is 0.47.

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.