If 8.60 grams of methane gas (hint: remember the fuel for the bunsen burner) is in a 2.00 l container at 66oc, what is the pressure in the container?

Data:

Gas: methane = CH4

V = 2.00 liter

T = 66°C = 66 + 273.15 K = 339.15 K

 Use the ideal gas equation pV = n RT

R = 0.082 atm*liter / K*mol

n is the number of moles and is calculated using the molar mass,MM, of CH4.

MM of CH4 = 12.0 g/mol + 4*1 g/mol = 16.0 g / mol

n = mass / MM = 8.60 g / 16.0 g/mol   = 0.5375 mol

Now you can use the formula: pV = nRT => p = nRT / V

p = 0.5375 mol * 0.082 atm*liter / K*mol * 339.15 K / 2.00 liter

p = 7.47 atm

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