450 moles of nacl are dissolved in 95.0 ml of water. calculate the molarity of the nacl solution.
a.0.0047 mb)0.21 mc)2.1 md)4.7 m

The answer is:  [D]:  "4.7 * 10³ M "

Note:

Molarity, "M", equals "moles of solutes per Liters solvent" ; or "mol / L ".

Given: "450 mol / 95.0 mL" ; convert to:  "mol/L" ("moles per unit Liter (L)" ) ;

Note: The exact measurement:  1000 mL = 1 L .

(450 mol / 95.0 mL) *(1000 mL / 1 L) = (450 * 1000) / (95.0) = 450000 / 95.0 =

         450000 mol / 95 L  ;  (note only "TWO (2) significant figures in 4
                                  "450000" ; so we can rewrite "95.0" as "95"                                                                         (only "2" significant figures).

 = (450000/95) mol / L =  4736.8421052631578947    ;
                                        → round to "2" significant figures ; 

                                        →   =   4.7 * 10³ moles / L  ;

                                        →   =   4.7 * 10³ M .

                 

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na