What pressure will be exerted by 10 moles of hydrogen gas in a 7.5 l cylinder at 20°c? (given: r = 8.314 l∙kpa/k∙mol)

3248.0 kPa of pressure will be exerted by 10 moles of hydrogen gas in a 7.5 L cylinder at 20°C.

Explanation:

Using ideal gas equation:  

PV = nRT

P= pressure = ?

V= volume =  

n = no of moles = 10 moles

R= gas constant =0.0821 kPaL\molK

T= temperature =

Thus pressure exerted is 3248.0 kPa

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

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explanation: