This is the equation for the dissociation of ammonia gas at 293 k. h = 145 kj and s = 195 j/k.

2nh3(g) n2(g) + 3h2(g)

which correctly states the g for this dissociation and whether the process is spontaneous or nonspontaneous? use g = h – ts.

We are given the equation for the dissociation of ammonia gas at 293 K. 

2NH3 (g) ==> N2(g) + 3H2(g)

and H = 145 kJ; S = 195 J/K

To determine the Gibb's Free Energy for this reaction, use the formula:

G = H - TS
substitute the given values:
G = 145x10^3 J - 293K * 195 J/K
G = 87865 Joules

The dissociation of ammonia gas has a positive Gibb's Free Energy, thus, the reaction is not spontaneous. Spontaneous reactions have Gibb's Free Energy which is less than zero or a negative number. 

Iwould you figure it out but you don't have a picture or in your question as to what the physical property you're looking for is