What volume of o2 at 874 mmhg and 33 ∘c is required to synthesize 18.0 mol of no?

490.93 liters is required to synthesize 18.0 mol of NO

Stokiometry in Chemistry learn about chemicals mainly emphasizes quantitative, such as the calculation of volume, mass, number, which is related to numbers, molecules, elements, etc.

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

In the reaction there are also manifestations of reagent substances namely gas (g), liquid (liquid / l), solid (solid / s) and solution (aqueous / aq).

Reactions that occur:

4NH₃ (g) + 5O₂ (g) -> 4NO (g) + 6H₂O (g)

Comparison of coefficient = mole ratio

So that mole O₂ = 5/4 x mol NO

mole O₂ = 5/4 x 18

mole O₂ = 22.5

To find the volume, assuming the ideal gas, we use the formula:

P = 874 mmhg = 874/760 mmhg = 1.15 atm

R = 0.082 L atm / mole K

T = 33 + 273 = 306 K

V = nRT / P

V = 22.5 0.082.306 / 1.15

V = 490.93 liters

the ideal gas law

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excess reactant

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the percentage yield

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limiting reactant

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Keywords: ideal gas law, mole, NO, O₂

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

i think its 100.

hope this !