What is the molecular formula of a compound with an empirical formula of c4h9 and a gram-formula mass of 114.0 g/mole?

The formula is easy:

Gram formula mass

Emprical Formula

So if we plug in our own numbers,

114.0

57.116 

We get an answer of 1.99, which rounds to 2.
Then, we distribute based off of our empirical formula.

2(C4H9) becomes C8H18.

Our molecular formula is C8H18.
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Ch4 and ph3 are both covalent since they are composed both of non-metals.    ch4 is non- polar because of  london forces and has a geometry of tetrahedral  ph3 , on the other hand, is umbrella shaped polar and has dipole-dipole intermolecular force (imf) . since ph3 is polar, it has a stronger imf