What is the molarity of solution prepared by dissolving 11.75 g of kno3 in enough water to produce 2.00 l of solution?

The molar mass of the compound potassium nitrate, KNO3 is equal to 101.1032 g/mol. Then, we determine the number of moles present in the given amount,
                       n = 11.75g / (101.1032 g/mol) = 0.116 mol
Then, molarity is calculated by dividing the number of moles by the volume of the solution. The answer is therefore 0.058 M. 

Ithink the answer is d.