What is the theoretical yield of sodium chloride for the reaction of 55.0 g na with 67.2 g cl2?

The chemical reaction would be written as:

2Na + Cl2 = 2NaCl

Since we are given the amounts of the reactants available for reaction, we have to determine the limiting reactant. And use this amount to calculate for the theoretical yield.

55 g Na ( 1 mol / 22.99 g ) = 2.39 mol Na
67.2 f Cl2 ( 1 mol / 70.9 g ) = 0.95 mol Cl2

Therefore, the limiting reactant would be Cl2 since it is the one consumed completely.

0.95 Cl2 ( 1 mol NaCl / 1 mol Cl2) = 0.95 NaCl produced from the reaction

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