If 86.1 g of nitrogen reacts with lithium, how many grams of lithium will react?

The amount of lithium reacted is 64.0215 grams.

Explanation:

To calculate the number of moles, we use the equation:

  ....(1)

Given mass of nitrogen = 86.1 g

Molar mass of nitrogen = 28 g/mol

Putting values in above equation, we get:

For the reaction of nitrogen and lithium, the chemical equation follows:

By Stoichiometry of the reaction:

1 mole of nitrogen reacts with 3 moles of lithium.

So, 3.075 moles of nitrogen will react with = moles of lithium.

Now, calculating the mass of lithium by using equation 1, we get:

Molar mass of lithium = 6.94 g/mol

Moles of lithium = 9.225 mol

Putting values in equation 1, we get:

Hence, the amount of lithium reacted is 64.0215 grams.

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