An ultraviolet wave traveling through a vacuum has a wavelength of 4.0 × 10^–7 m. the wave’s frequency, written in scientific notation to two significant figures, is
× 10^14 hz.
fill in the blank.

Answer :

Explanation : To find the frequency of the ultraviolet wave which is travelling through a vacuum having wavelength as .

we have the formula for finding the frequency which is given below;

Frequency =

Speed of light is a constant value which is .

Substituting the above values in the equation we get,

Frequency =

Which gives, Frequency = .

Therefore, the frequency of the ultraviolet in vacuum will be .

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.