If 3.59 grams of sodium chloride are consumed in the reaction, how many moles of sodium sulfate are produced.
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Consider the Reaction: 2 NaCl + BaSO₄ → Na₂SO₄ + BaCl₂

Here, Given mass of NaCl = 3.59 g
Molar mass of NaCl = 58 g/mol

Number of moles of NaCl = 2 (3.59 / 58) = 2(0.0618) = 0.123 mol

Now, for every 2 moles of NaCl, 1 mole of Na₂SO₄ formed.
So, number of moles of Na₂SO₄ = 0.123/2 = 0.0618

In short, Your Answer would be: 0.0618 moles

Hope this helps!

So what you would do is go through and add 3 teaspoons(tsp) 6 times because of the 6 tablespoons(tbsp). which will give you an answer of 18. another way is to multiply 3x6=18.