14.01 g sample of n2 reacts with 3.02 g of h2 to form ammonia (nh3). if ammonia is the only product, what mass of ammonia is formed?

N2 + 3H2 → 2NH3 
1Mol N2 reacts with 3 mol H2 to produce 2 mol NH3 
Determine the limiting reactant: 
Molar Mass N2 = 28.02 g/mol 
14.01g N2 = 14.01*28.02 = 0.5 mol N2 
This wiull react with 0.5*3 = 1.5 mol H2 
Molar mass H2 = 2.015 g/mol 
3.02g = 3.02/2.015 = 1.5 mol H2 

You reactants are in stoichiometric balance ( as close as you can get). 
Therefore 0.5 mol N2 will produce 1.0 mol NH3 
Molar mass NH3 = 14.0 + 1.01*3 = 17.03g NH3 produced - which is the mass of reactants because they are in stoichiometric balance.

Hope this helps xox :)

It would be true sodium reacts with water in a violent way