Suppose 4.2 mol of oxygen and 4.0 mol of no are introduced to an evacuated 0.50-l reaction vessel. at a specific temperature, the equilibrium 2no(g) + o2(g) picture 2no2(g) is reached when [no] = 1.6 m. calculate kc for the reaction at this temperature.

Answer : The value of for the reaction is, 3.9

Solution :  Given,

Moles of = 4.2 mol

Moles of = 4.0 mol

First we have to calculate the concentration of .

Now we have to calculate the value of equilibrium constant.

The given equilibrium reaction is,

Initially conc.       8.4       8.0          0

At eqm.             (8.4-2x)  (8.0-x)     2x

The expression of will be,

      .......(1)

The concentration of NO at equilibrium = 1.6 M = (8.4-2x)

So,

8.4 - 2x = 1.6

x = 3.4

Now put the value of 'x' in the above equation 1, we get:

Therefore, the value of for the reaction is, 3.9

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explanation:

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.