Mgnh4po4*6h2o, loses all water of hydration at what temperature?

T = 100 C (212 F)

Explanation:

'Water of hydration' is the terminology used to refer to the water molecules present in the crystals of a given substance that can be removed by heating the substance without altering its composition.

MgNH4PO4.6H2O is essentially magnesium ammonium phosphate which has  6 molecules of water of hydration. These can be removed stepwise by gradually increasing the temperature. At a final temperature of 100 C or 212 F the compound will lose all water of hydration.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.