Find the volume of 0.100 m hydrochloric acid necessary to react completely with 1.51 g al(oh)3.

The balanced chemical reaction is written as:

3HCl + Al(OH)3 = AlCl3 + 3H2O

We calculate as follows:

1.51 g Al(OH)3 ( 1 mol / 78.01 g ) ( 3 mol HCl / 1 mol Al(OH)3 ) ( 1 L / 0.100 mol HCl ) = 0.581 L of 0.100 M HCl solution is needed

Hope this answers the question. Have a nice day.

They are all full and don't need any more electrons in there outer shell.