How many atoms of phosphorus are in 5.20 mol of copper(ii) phosphate?

Data:
copper(II) phosphate
Formula: Cu3(PO4)2 

In each mol there are 6,02*10²³ atoms

Cu3 (PO4)2, observing the formula are 2 mol of P (Phosphorus) that is 2 times 6.02 * 10²³, which is equal to 12.04 * 10²³ atoms.

Therefore, in 5.20 mol of copper(II) phosphate?

5.20 * 12.04 * 10²³ ≈ 62.60*10²³atoms or 6,26*10^24 atoms

The mass has escaped into a gas which you can not see so the law stays true.