If 125 cal of heat is applied to 60.0 g piece of copper at 22.0 c, what will the final temperature be? the specific heat of cooper is 0.0920 cal/g

The final temperature will be 44.64 °C

Explanation:

Step 1: Data given

Amount of heat = 125 cal

Mass of copper = 60.0 grams

Initial temperature of copper = 22.0 °C

Specific heat of copper = 0.0920 cal/g

Step 2: Calculate the final temperature

Q = m*c*ΔT

⇒ Q = the heat transfer = 125 cal

⇒ m = the mass of copper = 60.0 grams

⇒ c = the specific heat of copper = 0.0920 cal/g°C

⇒ ΔT = the change in temperature = T2 - T1 = T2 - 22.0 °C

125 cal = 60.0 g * 0.0920 cal/g *  ΔT

ΔT = 22.64

ΔT = T2 - T1

T2 = 22.64 + 22.0 °C

T2 = 44.64 °C

The final temperature will be 44.64 °C

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.