You already saw that 1.00 g of al should yield 3.53 g of copper for the reaction below. 3cucl2(aq) + 2al(s)⟶ 2alcl3(aq) + 3cu(s) however, impurities and errors can occur easily. suppose that only 2.86 g of copper is produced. what is the percent yield of the reaction

81 %

Explanation:

Percent yield = actual yield/ theoretical yield x 100

Percent yield is the ratio of the actual yield to the theoretical yield  

Given,  

Actual yield = 2.86 g

Theoretical yield = 3.53 g  

Percent yield == 81 %

i think it is true since you can test the answer and can use observations to complete it.