When 10 grams of copper and 10 grams of iodine are mixed, what is the
theoretical yield of copper i iodide?
2cu + i2 → 2cui

30 grams

15 grams

7.5 grams

20 grams

15 grams

Explanation:

Mass of Cu = 10 g  

Molar mass of Cu = 63.546 g/mol

Moles of Cu =  = 0.1574

Mass of I₂ = 10 g  

Molar mass of I₂ = 253.8 g/mol

Moles of I₂ = = 0.04

I₂ here is the limiting reactant as it has the least number of moles.  

Based on the balanced equation,

1 mole of I₂ = 2 moles of CuI

0.04 mole of I₂ = 0.08 moles of CuI

Molar mass of CuI = 190.45 g/mol

Mass of CuI = 0.08 moles x 190.45 g/mol  = 15.236  g

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3