How many grams of chlorine gas must react to give 4.82g of bicl3?
2bi(s)+3cl2(
g.→2bicl3(s) my answer was wrong/ review and tell me where i went wrong.
4.82g bicl3*1mol bicl3/215.33g bicl3*3 mol cl2/2 mol bicl3* 70.9g cl2/1 mol cl2=6.50 g cl2

Count the number of each type of atom in the equation below, and then balance the equation. write in the numbers of atoms and coefficients. add a 1 if there should be no coefficient. cs2(l) + o2(g) → co2(g) + so2(g) c [ ] s [ ] o > c [ ] s [ ] o [ ] cs2(l) + [ ] o2(g) > [ ] co2(g) + [ ] so2(g)