6 moles of o₂ react. assume you have more than enough h₂s to react with it. how many moles of so₂ are produced?

a) 1 mole
b) 2moles
c) 4moles
d) 6moles
e) cannot be determined

C) 4moles

Explanation:

Let's consider the following balanced equation.

2 H₂S(g) + 3 O₂(g) → 2 SO₂(g) + 2 H₂O(g)

The molar ratio of O₂(g) to SO₂(g) is 3:2. The moles of SO₂(g) produced from the reaction of 6 moles of O₂(g) are:

6 mol O₂(g) × (2 mol SO₂(g)/ 3 mol O₂(g)) = 4 mol SO₂(g)

When 6 moles of O₂(g) react with more than enough H₂S(g), 4 moles of SO₂(g) are produced.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.