100 ml of 1.0 m formic acid (hcooh) is titrated with 1.0 m sodium hydroxide (naoh).
the approximate pka is 4 at the pka, what fraction of the carboxyl group will have been converted to coo-?

Fraction of carboxyl group that will have been converted to COO- = 50%

Explanation:

pKa of formic acid = 4

At pKa, titration is at equivalence point.

At equivalence point, number of moles of HCOOH undissociated is equal to number of moles of dissociated

Thus, fraction of carboxyl group that will have been converted to COO-:

fraction of carboxyl group that will have been converted to COO- = 50%

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.