How many moles of aluminum are needed to react with 3.6 mol of feo? 2al(s) + 3feo(s) > 3fe(s) + al^2o^3(s)
a. 2.4 mol
b. 2.1 mol
c. 1.2 mol
d. 0.8 mol

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

i would say b

explanation:

but i think i would need more information than that

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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