An unknown volume of gas has a pressure of 0.50 atm and temperature of 325 k. if the pressure is raised to 1.2 atm and the temperature decreased to 320 k, giving a new volume of 48 l, what was the initial volume?
a. 65 l
b. 87 l
c. 120 l
d. 140 l

You can solve this by using the equation (P1V1/T1) = (P2V2/T2). Plug in 0.50 atm for P1, leave V1 as the unknown, and plug in 325 K as T1. Then substitute 1.2 atm for P2, 48 L for V2, and 320 K for T2. Solve for V1, which is 117L, but since you round using two sig figs, your answer is C, 120 L. Hope this helps!

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.