How many moles of oxygen gas are needed to react completely with 17.9 ml mg, with a density of 1.74 g/ml?

unbalanced equation: mg + o2 “yields”/ mgo

0.212 mol o2

0.641 mol o2

1.28 mol o2

2.56 mol o2

For the answer to the question above, 17.9 x 1.74 gram Mg = 31.15 gram Mg = (31.15/24.31) = 1.28 mole Mg 

2 Mg + O2 ---> 2MgO 

so 1.28 mole Mg reacts with 0.641 mole O2

I hope my answer helped you. Feel free to ask more questions. Have a nice day!

Idon’t know what the answer is i wish i could