If there are 40 mol of nbr3 and 48 mol of naoh, what is the excess reactant?

a) n2
b) nbr3
c) naoh
d) hobr

Answer : The correct option is (B)

Solution : Given,

Moles of = 40 mol

Moles of = 48 mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 3 mole of react with 2 mole of

So, 48 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Excess moles of = 40 - 32 = 8 moles

Hence, the correct option is (B)