element 106 has a half life of 0.9 seconds. if 250.0 grams of it were prepared how many grams will remain after 4.5 seconds​

  the moles   of   sulfuric acid   that are needed to react   completely with 6.4   moles   of lithium hydroxide   is 12.8   moles ( answer a)

calculation

step 1 : write a balanced   chemical equation

2lioh   + h₂so₄   →   li₂so₄   +2h₂o

step 2 : use the mole ratio   to determine   the   moles h₂so₄

from   equation above   lioh: h₂so₄   is 2: 1 therefore   the moles of h₂so₄

= 6.4   x 2/1   = 12.8   moles   of h₂so₄