4. If 52.0 g of magnesium react with excess hydrochloric acid, how many liters of hydrogen gas can be made at 300 K and 0.970 atm?

 54.8 Liters of hydrogen gas can be made at 300 K and 0.970 atm

Explanation:

To calculate the moles, we use the equation:

The balanced chemical equation is:

According to stoichiometry:

1 mole of Mg gives = 1 mole of

Thus 2.16 moles of Mg give = of

According to ideal gas equation:

P = pressure of gas = 0.970 atm

V = Volume of gas = ?

n = number of moles = 2.16

R = gas constant =

T =temperature =

Thus 54.8 Liters of hydrogen gas can be made at 300 K and 0.970 atm

- lead + phosphoric acid = hydrogen + lead(ii) phosphate